2d^2+9d+6=0

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Solution for 2d^2+9d+6=0 equation: 



2d^2+9d+6=0

a = 2; b = 9; c = +6;
Δ = b2-4ac
Δ = 92-4·2·6
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{33}}{2*2}=\frac{-9-\sqrt{33}}{4}
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{33}}{2*2}=\frac{-9+\sqrt{33}}{4}
$

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